Prerequisites: Theorem A (energy isolation), Sinclair–Jerrum bound (Fact B.6).
Theorem D. Let F∈Ft and X0∼πF. The escape time from F under the lazy walk P~t satisfies:
E[Tesc(F)]≥2θ1.
Proof. (Complete.)
Step 1 (Restricted chain). Define the restricted sub-stochastic matrix on F:
PF(i,j):=dt(i)Wt(i,j)(i,j∈F),P~F:=21(I∣F+PF).
Row sums: ∑j∈FP~F(i,j)=21(1+1−rF,t(i))=1−2rF,t(i)<1.
Step 2 (Conductance bound). The conductance of the restricted chain on F (with absorbing boundary) is:
ΦF:=∅=S⊊FminπF(S)∑i∈S∑j∈F∖SP~F(i,j)πF(i)+∑i∈S2rF,t(i)πF(i)
where πF(i)∝dt(i) restricted to F.
The numerator's first term is the internal flow out of S within F; the second term is the leakage from S to the exterior. Consider the cut of S within the full graph. For any S⊊F:
i∈S∑j∈/S∑Pt(i,j)πF(i)=volt(F)cutt(S,V∖S)⋅volt(S).
In the worst case (taking S to be F itself with absorbing exterior), the effective conductance is bounded by ϕt(F). More precisely, for any S⊊F with volt(S)≤21volt(F):
ΦF(S)≤volt(S)cutt(S,Sˉ)≤ϕt(S).
Taking the minimum over S: ΦF≤ϕt(F)≤θ.
Step 3 (Spectral gap). By the Sinclair–Jerrum bound (Fact B.6): γF≤2ΦF≤2θ. For the lazy chain: γ~F=γF/2≤θ.
Step 4 (Escape time). The expected absorption time from the quasi-stationary distribution satisfies (see Aldous–Fill, Theorem 12.4; or Montenegro–Tetali, Theorem 3.3):
EπF[Tesc]≥2γ~F1≥2θ1.
The factor 21 arises because, for a lazy chain with spectral gap γ~, the relaxation time is 1/γ~, and the mean hitting time to an absorbing set from the stationary distribution is at least 21⋅γ~1 (Aldous–Fill inequality for reversible absorbing chains). □
Explicit constant. The bound 2θ1 is tight up to constant factors. For a barbell graph (two complete graphs of size n/2 connected by a single edge of weight ϵ), the conductance is Θ(ϵ/n) and the escape time is Θ(n/ϵ).