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Door

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  1. #1

    (i) Each has , so:

    τΣτiΣτbF,t(i)iFbF,t(i)=cutt(F,Fˉ)θvolt(F).\tau\cdot|\Sigma_\tau|\le\sum_{i\in\Sigma_\tau}b_{F,t}(i)\le\sum_{i\in F}b_{F,t}(i)=\mathrm{cut}_t(F,\bar F)\le\theta\cdot\mathrm{vol}_t(F).